Atomic masses: $X_{1}^{1} X_{21}^{21} H$ = $1.007825 u$ , $X_{1}^{2} X_{21}^{22} H$ = $2.014102 u$ , neutron = $1.008665 u$ ; $1 u = 931.5 MeV / c^{2}$ . The binding energy per nucleon of the deuteron is closest to

A2.22 MeV
B1.11 MeV
C0.56 MeV
D4.45 MeV

Answer: B

Using atomic masses, the electron masses cancel. Mass defect = 1.007825 + 1.008665 - 2.014102 = 0.002388 u. Binding energy = 0.002388 x 931.5 = 2.224 MeV. Per nucleon: 2.224/2 = 1.11 MeV.

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Atomic masses: X11​X2121​H = 1.007825 u, X12​X2122​H = 2.014102 u, neutron = 1.008665 u; 1 u=931.5 MeV/c2. The binding energy per nucleon of the deuteron is closest to

Answer: B

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Atomic masses: $X_{1}^{1} X_{21}^{21} H$ = $1.007825 u$ , $X_{1}^{2} X_{21}^{22} H$ = $2.014102 u$ , neutron = $1.008665 u$ ; $1 u = 931.5 MeV / c^{2}$ . The binding energy per nucleon of the deuteron is closest to