JEE Advanced levelSingle correct optionDifficulty 3 of 3as040
An isolated, initially neutral metal sphere of radius 5.0cm and work function 2.0eV is illuminated by light of wavelength 250nm. Photoelectrons leave until the sphere's potential stops further emission. Use h=6.626×10−34Js, c=3.0×108ms−1, e=1.6×10−19C, 1/(4πϵ0)=9.0×109Nm2C−2. The number of electrons emitted is closest to
A2.06×108
B6.94×107
C1.03×108
D1.73×108
Answer: C
Photon energy = 4.969 eV, so the maximum KE is 4.969 - 2.0 = 2.969 eV. Emission stops when the sphere reaches V = 2.969 V. Charge Q = 4 pi eps0 r V = (0.05)(2.969)/(9.0e9) = 1.650e-11 C. Number of electrons = Q/e = 1.031e+08.