The number of neutrons in 7.0 g of ^14_6C is closest to (take molar mass 14 g mol^-1 and N_A=6.022x10^23 mol^-1)

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The number of neutrons in $7.0 g$ of $X_{6}^{14} X_{26}^{214} C$ is closest to (take molar mass $14 g mo l^{- 1}$ and $N_{A} = 6.022 \times 1 0^{23} mo l^{- 1}$ )

A $1.807 \times 1 0^{24}$
B $4.215 \times 1 0^{24}$
C $1.204 \times 1 0^{24}$
D $2.409 \times 1 0^{24}$

Answer: D

Moles of atoms = 7.0/14 = 0.5. Neutrons per atom = 14 - 6 = 8. Total neutrons = 0.5 x 8 x 6.022e23 = 2.409e+24. Using 6 per atom (protons) gives 1.807e+24, using 14 gives 4.215e+24.

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The number of neutrons in 7.0 g of X614​X26214​C is closest to (take molar mass 14 gmol−1 and NA​=6.022×1023 mol−1)

Answer: D

More questions on Subatomic particles, atomic models, nucleus

The number of neutrons in $7.0 g$ of $X_{6}^{14} X_{26}^{214} C$ is closest to (take molar mass $14 g mo l^{- 1}$ and $N_{A} = 6.022 \times 1 0^{23} mo l^{- 1}$ )