JEE Advanced levelNumerical answerDifficulty 3 of 3as045
Take the radius of an aluminium-27 nucleus as R=1.2×10−15A1/3m and the radius of the atom as 1.5×10−10m. The fraction of the atomic volume occupied by the nucleus is x×10−14. Find x to two decimals.
Numerical answer type, tolerance 0.05.
Answer: 1.38
R = 1.2e-15 x 271/3 = 1.2e-15 x 3 = 3.60e-15 m. Volume ratio = (R/ratom)3 = (3.60e−15/1.5e−10)3 = 1.382e-14, so x = 1.38.