Light of frequency $9.2\times 10^{14}\mathrm{Hz}$ falls on a metal of work function $2.4\mathrm{eV}$. Find the stopping potential in volts, to two decimals. Use $h=6.626\times 10^{-34}\mathrm{J}\mathrm{s}$ and $1\mathrm{eV}=1.6\times 10^{-19}\mathrm{J}$.

Numerical answer type, answer in V, tolerance 0.02.