Supercooled liquid water freezes at 263 K and 1 bar. Take Delta_fusH = 6010 J mol^-1 at 273 K (normal melting point), with Delta H and Delta S of fusion independent of temperature. For freezing of 1 mol at 263 K, select the correct statement(s).

Delta S_system approx -22.0 J K^-1

Delta S_universe approx +0.84 J K^-1

Delta G approx -220 J, so freezing is spontaneous

Delta S_system approx -22.0 J K^-1

Delta S_surroundings approx +22.0 J K^-1

Delta S_universe approx +0.84 J K^-1

Delta G approx -220 J, so freezing is spontaneous

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3td109

Supercooled liquid water freezes at $263 K$ and $1 bar$ . Take $Δ_{f u s} H = 6010 J mo l^{- 1}$ at $273 K$ (normal melting point), with $Δ H$ and $Δ S$ of fusion independent of temperature. For freezing of $1 mol$ at $263 K$ , select the correct statement(s).

Δ S_{f u s} = 6010/273 = 22.01 J K^{- 1}

, so freezing has

Δ S_{sys} = - 22.01

and

Δ H = - 6010 J

Δ G = - 6010 + 263 (22.01) = - 220 J

(negative).

Δ S_{s u rr} = 6010/263 = 22.85 J K^{- 1}

, not

22.01

because the heat is received at

263 K

Δ S_{u ni v} = 22.85 - 22.01 = 0.84 J K^{- 1} > 0

, and equals

- Δ G / T