For a reaction, Delta H deg = -112.0 kJ mol^-1 and Delta S deg = -218 J K^-1mol^-1. Calculate Delta G deg at 298 K in kJ mol^-1 (nearest integer).

JEE Main levelNumerical answerDifficulty 2 of 3td096

For a reaction, $Δ H^{\circ} = - 112.0 kJ mo l^{- 1}$ and $Δ S^{\circ} = - 218 J K^{- 1} mo l^{- 1}$ . Calculate $Δ G^{\circ}$ at $298 K$ in $kJ mo l^{- 1}$ (nearest integer).

Numerical answer type, answer in kJ/mol, tolerance 0.5.

Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ} = - 112.0 - 298 (- 0.218) = - 112.0 + 64.96 = - 47.04 kJ mo l^{- 1}