MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Thermodynamics and Thermochemistry
/
Gibbs energy, spontaneity and relation to equilibrium constant
NEET level
Single correct option
Difficulty 1 of 3
td094
If the equilibrium constant
K
of a reaction at
298
K
is greater than 1, then its standard Gibbs energy change is
A
zero
B
equal to
RT
ln
K
C
positive
D
negative
Answer: D
Δ
G
∘
=
−
RT
ln
K
. For
K
>
1
,
ln
K
>
0
, so
Δ
G
∘
<
0
. The expression
RT
ln
K
has the wrong sign.
Practice Thermodynamics and Thermochemistry
More on Gibbs energy, spontaneity and relation to equilibrium constant
Previous question
Next question
More questions on Gibbs energy, spontaneity and relation to equilibrium constant
At constant temperature and pressure, a process is spontaneous when
NEET level
A reaction with Delta H < 0 and Delta S > 0 is
NEET level
For a reaction, Delta H deg = -112.0 kJ mol^-1 and Delta S deg = -218 J K^-1mol^-1. Calculate Delta G deg at 298 K in kJ mol^-1 (nearest int...
JEE Main level
A reaction has Delta H deg = +55.3 kJ mol^-1 and Delta S deg = +132.0 J K^-1mol^-1 (both independent of temperature). Above what temperature...
JEE Main level
For a reaction at 298 K, Delta G deg = -25.0 kJ mol^-1. Calculate log_10K (two decimals). Use R = 8.314 J mol^-1K^-1 and 2.303 for ln 10.
JEE Main level
The equilibrium constant of a reaction at 298 K is 1.0 x 10^-3. Using 2.303RT = 5.71 kJ mol^-1, Delta G deg is
JEE Main level