A double-reciprocal (Lineweaver-Burk) plot of $1/v$ against $1/[S]$ for an enzyme is a straight line with slope $0.150$ and intercept $0.0250$ (with $v$ in $\mu \mathrm{M}\mathrm{mi}{\mathrm{n}}^{-1}$ and $[S]$ in mM, so slope has units $\min \mathrm{mM}\mu {\mathrm{M}}^{-1}$). Using $1/v=(K_m/V_{max})(1/[S])+1/V_{max}$, the values are

1. A$K_m=0.15\mathrm{mM}$, $V_{max}=0.025\mu \mathrm{M}\mathrm{mi}{\mathrm{n}}^{-1}$
2. B$K_m=6.0\mathrm{mM}$, $V_{max}=0.025\mu \mathrm{M}\mathrm{mi}{\mathrm{n}}^{-1}$
3. C$K_m=6.0\mathrm{mM}$, $V_{max}=40\mu \mathrm{M}\mathrm{mi}{\mathrm{n}}^{-1}$
4. D$K_m=40\mathrm{mM}$, $V_{max}=6.0\mu \mathrm{M}\mathrm{mi}{\mathrm{n}}^{-1}$