JEE Advanced levelSingle correct optionDifficulty 3 of 3sc091
A catalyst bed produces 8.0mol of product per hour when fresh. After a poison blocks 70% of its active sites, the rate is proportional to the fraction of free sites. The time needed to make 5.04mol of product with the poisoned catalyst is
A126 min
B54 min
C180 min
D37.8 min
Answer: A
Free sites =30%, so rate =0.30×8.0=2.4molh−1. Time =5.04/2.4=2.1h=126min. The value 54 min wrongly uses 70% of sites and 37.8 min ignores poisoning.