JEE Advanced levelNumerical answerDifficulty 3 of 3sc097
An enzyme lowers the activation energy of a reaction from 90kJmol−1 to 45kJmol−1 at 310K with equal pre-exponential factors. Calculate the power of ten x in kcat/kuncat=10x, to one decimal. Use R=8.314Jmol−1K−1 and 2.303 for ln10.
Numerical answer type, tolerance 0.05.
Answer: 7.6
x=ΔEa/(2.303RT)=45000/(2.303×8.314×310)=7.581, i.e. 7.6.