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JEE Main levelNumerical answerDifficulty 2 of 3sc022

For adsorption of a gas on charcoal, $x / m = k p^{1/ n}$ with $k = 2.4 mg g^{- 1} at m^{- 1/n}$ and $1/ n = 0.40$ . Calculate $x / m$ in $mg g^{- 1}$ at $p = 3.0 atm$ . Use $3^{0.4} = 1.55$ if needed; give the answer to one decimal place.

Numerical answer type, answer in mg/g, tolerance 0.1.

Answer: 3.7 mg/g

x / m = 2.4 \times 3. 0^{0.40}

. Since

3^{0.40} = 1.552

,

x / m = 2.4 \times 1.552 = 3.72

, i.e. about

3.7 mg g^{- 1}

.

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