In a Freundlich study, $x / m = 1.5 g/g$ at $p = 0.20 atm$ and $x / m = 4.5 g/g$ at $p = 1.8 atm$ . The data fit $x / m = k p^{1/ n}$ with $n = 2$ exactly. Calculate $k$ (in $g g^{- 1} at m^{- 1/2}$ ) to two decimal places.

Numerical answer type, answer in g g^-1 atm^-1/2, tolerance 0.02.

Answer: 3.3541 g g^-1 atm^-1/2

The ratio of pressures is

1.8/0.20 = 9

and the ratio of

x / m

3 = 9^{1/2}

, confirming

n = 2

. Then

k = 4.5/1. 8^{0.5} = 4.5/1.3416 = 3.35