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JEE Main levelSingle correct optionDifficulty 2 of 3sc019

A log-log plot for adsorption of a gas on a solid is linear with slope $0.50$ and intercept $0.602$ on the $lo g (x / m)$ axis (take $lo g 4 = 0.602$ ). The value of $x / m$ (same units as used for the plot) at $p = 9$ is:

A $12$
B $18$
C $36$
D $6$

Answer: A

Intercept

= lo g k = 0.602

, so

k = 4

; slope

= 1/ n = 0.50

. Then

x / m = 4 \times 9^{0.5} = 12

. Using

4 \times 9 \times 0.5 = 18

or

4 \times 9 = 36

are typical slips.

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