A hydrocarbon C5H10 undergoes ozonolysis followed by Zn/H2O to give ethanal and propanone. The hydrocarbon is

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A hydrocarbon $C X_{5} H X_{10}$ undergoes ozonolysis followed by $Zn / H X_{2} O$ to give ethanal and propanone. The hydrocarbon is

A3-methylbut-1-ene
Bpent-2-ene
C2-methylbut-2-ene
D2-methylbut-1-ene

Answer: C

Joining the two carbonyl carbons by a double bond gives

CH X_{3} CH = C (CH X_{3}) X_{2}

, 2-methylbut-2-ene. Pent-2-ene would give ethanal and propanal, 2-methylbut-1-ene would give propanone and methanal, and 3-methylbut-1-ene would give 2-methylpropanal and methanal.

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Answer: C

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A hydrocarbon $C X_{5} H X_{10}$ undergoes ozonolysis followed by $Zn / H X_{2} O$ to give ethanal and propanone. The hydrocarbon is