A compound C2H6O liberates hydrogen with sodium and on oxidation with excess acidified K2Cr2O7 gives a compound C2H4O2. The compound is

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A compound $C X_{2} H X_{6} O$ liberates hydrogen with sodium and on oxidation with excess acidified $K X_{2} Cr X_{2} O X_{7}$ gives a compound $C X_{2} H X_{4} O X_{2}$ . The compound is

Evolution of

H X_{2}

with sodium shows an O-H group, so the compound is an alcohol and not an ether.

CH X_{3} CH X_{2} OH

is oxidised to

CH X_{3} COOH

(

C X_{2} H X_{4} O X_{2}

). Ethanal and ethanoic acid do not have the formula

C X_{2} H X_{6} O