Answer: D
The left structure has descriptors S at C2 and R at C4; reversing both wedges gives R at C2 and S at C4 in the right structure. Since C2 and C4 carry identical groups, numbering the chain from the other end converts (2R,4S) into (2S,4R). Both structures are the meso form of 2,4-dibromopentane, which has a mirror plane through C3. A meso compound is superimposable on its mirror image, so the two drawings represent the same compound.