The two structures shown (left and right) are 3-chlorobutan-2-ol drawn in two different orientations. They are related as

Rather than comparing wedges directly, assign CIP descriptors. In the left structure the carbon bearing OH is $S$ and the carbon bearing Cl is $R$, i.e. (2S,3R). In the right structure the chain is drawn from the other end, but the carbon bearing OH is again $S$ and the carbon bearing Cl is again $R$. Same constitution and same configuration at every centre means the two drawings represent the same compound.