The two structures shown (left and right) are stereoisomers of tartaric acid. They are related as

Adiastereomers
Benantiomers
Cconstitutional isomers
Didentical (same compound)

Answer: B

Priorities at each centre are OH, then COOH, then CH(OH)COOH, then H. The left structure is (2R,3R)-tartaric acid and the right one is (2S,3S). Both centres are inverted, so the structures are mirror images. Since (R,R) has no internal mirror plane (both descriptors are the same), it is chiral, and its mirror image (S,S) is a different compound: they are enantiomers. Note that this pair is different from the meso (2R,3S) form.

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