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JEE Advanced levelSingle correct optionDifficulty 3 of 3so144

A $2.5 M$ aqueous $NaOH$ solution has density $1.10 g m L^{- 1}$ (molar masses: $NaOH$ 40, water 18 $g mo l^{- 1}$ ). The mole fraction of $NaOH$ in the solution is closest to

A0.0450
B0.0431
C0.0393
D0.9569

Answer: B

Take 1 L: mass

= 1100

g,

NaOH = 2.5 \times 40 = 100

g, so water

= 1000

g

= 55.56

mol.

x = 2.5/ (2.5 + 55.56) = 0.0431

. Using 1100 g as water would give 0.0393.

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