JEE Main levelNumerical answerDifficulty 2 of 3so126
The solubility of OX2 in water at 298K is 1.3×10−3molL−1atm−1 (concentration =kHp). Air contains 21%OX2 by volume at 1.0 atm. Find the mass of OX2 (molar mass 32gmol−1) dissolved in 2.0 L of water at equilibrium with air. Give the answer in mg to one decimal place.
Numerical answer type, answer in mg, tolerance 0.1.
Answer: 17.5 mg
Partial pressure of OX2 is 0.21 atm. Concentration =1.3×10−3×0.21=2.73×10−4 mol/L. Moles in 2.0 L =5.46×10−4 mol, mass =5.46×10−4×32=0.01747 g =17.5 mg.