A $0.10 M$ solution of a binary electrolyte $AB$ ( $AB A X^{+} + B X^{-}$ ) shows an osmotic pressure of $4.43$ atm at $300 K$ . Use $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ and $i = 1 + α$ . Find the degree of dissociation $α$ (two decimal places).

Numerical answer type, tolerance 0.01.

Answer: 0.8

π = i CRT

, so

i = 4.43/ (0.10 \times 0.0821 \times 300) = 4.43/2.463 = 1.799

. For a binary electrolyte

i = 1 + α

, so

α = 1.799 - 1 = 0.799 \approx 0.80