Calculate the osmotic pressure at $310 K$ of a $0.150 M$ aqueous glucose solution. Use $R = 8.314 J mo l^{- 1} K^{- 1}$ with concentration in $mol m^{- 3}$ . Give the answer in kPa, to the nearest integer.

Numerical answer type, answer in kPa, tolerance 1.

Answer: 387 kPa

C = 0.150

mol/L

= 150

mol/m

^{3}

π = CRT = 150 \times 8.314 \times 310 = 386601

= 386.6

kPa, i.e. about 387 kPa.