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JEE Advanced levelSingle correct optionDifficulty 3 of 3so037

An ideal liquid mixture contains components A, B and C in the mole ratio $2 : 3 : 5$ . The pure vapour pressures are $120$ , $80$ and $40 torr$ respectively. The mole fraction of C in the equilibrium vapour is

A0.500
B0.333
C0.294
D0.200

Answer: C

Partial pressures: A

= 0.2 \times 120 = 24

, B

= 0.3 \times 80 = 24

, C

= 0.5 \times 40 = 20

torr; total

= 68

torr.

y_{C} = 20/68 = 0.294

. The liquid value

0.5

ignores that C is the least volatile.

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