JEE Advanced levelSingle correct optionDifficulty 3 of 3so036
Two ideal solutions of A and B are made at one temperature, with pA0=500torr and pB0=100torr. Solution 1 has xA=0.20 and solution 2 has xA=0.60. If 2.0mol of solution 1 is mixed with 3.0mol of solution 2, the total vapour pressure of the resulting solution is
A260torr
B276torr
C244torr
D300torr
Answer: B
Moles of A =2.0×0.20+3.0×0.60=2.2 in 5.0 mol, so xA=0.44. P=100+0.44×400=276torr. The unweighted average of 180 and 340 gives 260, and reversing the weights gives 244.