A metal of molar mass 50.0 g mol^-1 crystallises in a bcc lattice with edge 300 pm. Use N_A = 6.022x10^23 mol^-1. Calculate its density in g cm^-3 (two decimals).

JEE Main levelNumerical answerDifficulty 2 of 3ss120

A metal of molar mass $50.0 g mo l^{- 1}$ crystallises in a bcc lattice with edge $300 pm$ . Use $N_{A} = 6.022 \times 1 0^{23} mo l^{- 1}$ . Calculate its density in $g c m^{- 3}$ (two decimals).

Numerical answer type, answer in g/cm^3, tolerance 0.02.

Z = 2

for bcc.

ρ = \frac{ZM}{N _{A} a ^{3}} = \frac{2 \times 50.0}{6.022 \times 1 0 ^{23} \times ( 3.00 \times 1 0 ^{- 8} ) ^{3}} = 6.15 g c m^{- 3}