Anhydrous calcium nitrate decomposes on strong heating as 2Ca(NO3)2 -> 2CaO + 4NO2 + O2. Taking Ca 40, N 14, O 16, find the mass of gaseous products formed from 7.50 g of Ca(NO3)2, in g, to two decimal places.

JEE Main levelNumerical answerDifficulty 2 of 3sb099

Anhydrous calcium nitrate decomposes on strong heating as $2 Ca (NO X_{3}) X_{2} 2 CaO + 4 NO X_{2} + O X_{2}$ . Taking Ca 40, N 14, O 16, find the mass of gaseous products formed from 7.50 g of $Ca (NO X_{3}) X_{2}$ , in g, to two decimal places.

Numerical answer type, answer in g, tolerance 0.01.

Molar mass of

Ca (NO X_{3}) X_{2}

is 164 g/mol and 7.50 g is 0.04573 mol. The solid residue

CaO

(56 g/mol) has mass

0.04573 \times 56 = 2.561

g. Gas mass

= 7.50 - 2.561 = 4.94