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JEE Main levelSingle correct optionDifficulty 2 of 3sb097

A white powder dissolves completely in dilute HCl with effervescence when it is $BaCO X_{3}$ but remains undissolved when it is $BaSO X_{4}$ . The reason is

ABaSO4 has a lower lattice enthalpy than BaCO3
Bcarbonate ion reacts with H+ to give $CO X_{2}$ and water, whereas sulphate is the anion of a strong acid and its salt is not decomposed by dilute acid
CBa2+ is oxidised by the acid in BaSO4
DBaCO3 is soluble in water whereas BaSO4 is not

Answer: B

BaCO X_{3} + 2 HCl BaCl X_{2} + CO X_{2} + H X_{2} O

because the weak, unstable carbonic acid removes carbonate. Sulphate is the conjugate base of a strong acid, so H+ cannot remove it from the lattice and BaSO4 stays undissolved. BaCO3 is also water-insoluble.

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