Take ionic radii $Cs X^{+}$ = 167 pm and $Cl X^{-}$ = 181 pm. Using the radius ratio ranges 0.225-0.414 (tetrahedral), 0.414-0.732 (octahedral) and 0.732-1.000 (cubic), the coordination number of Cs+ in CsCl is

Answer: C

The radius ratio is

167/181 = 0.92

, which lies in the cubic range 0.732-1.000. A cubic hole means each Cs+ is surrounded by 8 chloride ions, so the coordination number is 8 (6 would apply to NaCl).

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Take ionic radii CsX+ = 167 pm and ClX− = 181 pm. Using the radius ratio ranges 0.225-0.414 (tetrahedral), 0.414-0.732 (octahedral) and 0.732-1.000 (cubic), the coordination number of Cs+ in CsCl is

Answer: C

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Take ionic radii $Cs X^{+}$ = 167 pm and $Cl X^{-}$ = 181 pm. Using the radius ratio ranges 0.225-0.414 (tetrahedral), 0.414-0.732 (octahedral) and 0.732-1.000 (cubic), the coordination number of Cs+ in CsCl is