N-Methylethanamide, CH3-CO-NH-CH3, is heated with excess LiAlH4 in ether and then treated with water. The product is

N-methylethanamine, CH3CH2-NH-CH3

JEE Main levelSingle correct optionDifficulty 2 of 3ro120

N-Methylethanamide, $CH X_{3} - CO - NH - CH X_{3}$ , is heated with excess $LiAlH X_{4}$ in ether and then treated with water. The product is

LiAlH X_{4}

reduces amides to amines: the C=O oxygen is removed and becomes

CH X_{2}

, in contrast to esters, where the C-O single bond breaks.

CH X_{3} CONHCH X_{3}

becomes

CH X_{3} CH X_{2} NHCH X_{3}