1.00 mol of 4-nitrocinnamaldehyde, $O X_{2} N - C X_{6} H X_{4} - CH = CH - CHO$ (nitro group on the ring para to the side chain), is hydrogenated with excess $H X_{2}$ over Pd-C at 1 atm and room temperature until uptake stops. Assume the benzene ring is not reduced, the nitro group goes to $NH X_{2}$ , the aldehyde goes to $CH X_{2} OH$ and no hydrogenolysis occurs. How many moles of $H X_{2}$ are absorbed? (Give an integer.)

Numerical answer type, tolerance 0.5.

Answer: 5

NO X_{2} NH X_{2}

needs 3

H X_{2}

, the

C = C

needs 1 and

CHO CH X_{2} OH

needs 1. Total

= 3 + 1 + 1 = 5

mol of

H X_{2}

, giving 3-(4-aminophenyl)propan-1-ol.