5-Methoxypent-2-yne is CH3-C#C-CH2CH2-O-CH3. Which statements are correct?

H2 over Lindlar catalyst gives (Z)-5-methoxypent-2-ene.

Na in liquid NH3 gives (E)-5-methoxypent-2-ene.

Excess H2 over Pd-C gives 1-methoxypentane.

H2 over Lindlar catalyst gives (Z)-5-methoxypent-2-ene.

Na in liquid NH3 gives (E)-5-methoxypent-2-ene.

Excess H2 over Pd-C gives 1-methoxypentane.

Na in liquid NH3 and H2/Lindlar give the same stereoisomer of the alkene.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ro019

5-Methoxypent-2-yne is $CH X_{3} - C \equiv C - CH X_{2} CH X_{2} - O - CH X_{3}$ . Which statements are correct?

A $H X_{2}$ over Lindlar catalyst gives (Z)-5-methoxypent-2-ene.
BNa in liquid $NH X_{3}$ gives (E)-5-methoxypent-2-ene.
CExcess $H X_{2}$ over Pd-C gives 1-methoxypentane.
DNa in liquid $NH X_{3}$ and $H X_{2}$ /Lindlar give the same stereoisomer of the alkene.

Lindlar gives syn addition (Z); Na/

NH X_{3}

gives anti addition (E); full hydrogenation gives

CH X_{3} CH X_{2} CH X_{2} CH X_{2} CH X_{2} OCH X_{3}

with the ether intact. The two partial reductions give opposite stereoisomers, so D is false.