Methyl 4-acetylbenzoate is CH3CO-C6H4-COOCH3 (substituents at positions 1 and 4 of the benzene ring). Which statements are correct?

NaBH4 in methanol gives methyl 4-(1-hydroxyethyl)benzoate.

Excess LiAlH4 followed by H3O+ gives [4-(1-hydroxyethyl)phenyl]methanol.

NaBH4 in methanol gives methyl 4-(1-hydroxyethyl)benzoate.

Excess LiAlH4 followed by H3O+ gives [4-(1-hydroxyethyl)phenyl]methanol.

NaBH4 in methanol reduces both the ketone and the ester.

H2 (1 atm), Pd-C at room temperature reduces the ester group to -CH2OH.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ro018

Methyl 4-acetylbenzoate is $CH X_{3} CO - C X_{6} H X_{4} - COOCH X_{3}$ (substituents at positions 1 and 4 of the benzene ring). Which statements are correct?

A $NaBH X_{4}$ in methanol gives methyl 4-(1-hydroxyethyl)benzoate.
BExcess $LiAlH X_{4}$ followed by $H X_{3} O X^{+}$ gives [4-(1-hydroxyethyl)phenyl]methanol.
C $NaBH X_{4}$ in methanol reduces both the ketone and the ester.
D $H X_{2}$ (1 atm), Pd-C at room temperature reduces the ester group to $- CH X_{2} OH$ .

NaBH X_{4}

reduces the ketone only, leaving the ester (A true, C false).

LiAlH X_{4}

reduces both groups to alcohols (B true). Pd-C at 1 atm does not reduce esters (D false).