JEE Main levelNumerical answerDifficulty 2 of 3rx188
To standardise a KMnOX4 solution, 0.335 g of pure sodium oxalate, NaX2CX2OX4 (molar mass 134), is dissolved in dilute HX2SOX4 and titrated hot, needing 41.7 mL of the permanganate solution. Find the molarity of the KMnOX4 solution, to three decimal places.
Numerical answer type, answer in M, tolerance 0.0005.
Answer: 0.024 M
mmol oxalate = 0.335/134 x 1000 = 2.50. From 2MnOX4X−+5CX2OX4X2−, mmol MnOX4X− = 2.50 x 2/5 = 1.00. Molarity = 1.00/41.7 = 0.0240 M.