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JEE Main levelNumerical answerDifficulty 2 of 3rx188

To standardise a solution, 0.335 g of pure sodium oxalate, (molar mass 134), is dissolved in dilute and titrated hot, needing 41.7 mL of the permanganate solution. Find the molarity of the solution, to three decimal places.

Numerical answer type, answer in M, tolerance 0.0005.

Answer: 0.024 M

mmol oxalate = 0.335/134 x 1000 = 2.50. From , mmol = 2.50 x 2/5 = 1.00. Molarity = 1.00/41.7 = 0.0240 M.
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