0.72 g of ferrous oxalate, FeC2O4 (molar mass 144), is titrated in acidic medium with 0.02 M KMnO4. Both Fe^2+ and the oxalate are oxidised (Fe^3+ and CO2 formed). The volume of KMnO4 required is:

JEE Main levelSingle correct optionDifficulty 2 of 3rx185

0.72 g of ferrous oxalate, $FeC X_{2} O X_{4}$ (molar mass 144), is titrated in acidic medium with 0.02 M $KMnO X_{4}$ . Both $Fe X^{2 +}$ and the oxalate are oxidised ( $Fe X^{3 +}$ and $CO X_{2}$ formed). The volume of $KMnO X_{4}$ required is:

mmol of

FeC X_{2} O X_{4}

= 0.72/144 x 1000 = 5.0. n-factor = 1 (Fe) + 2 (oxalate) = 3, so meq = 15. Normality of

KMnO X_{4}

= 0.10 N, so V = 15/0.10 = 150 mL.