JEE Main levelNumerical answerDifficulty 2 of 3rx189
The calcium in a 100 mL sample of hard water is precipitated as CaCX2OX4, filtered, dissolved in dilute HX2SOX4 and titrated with 0.0100 M KMnOX4, which needs 12.4 mL. Express the hardness as ppm (mg per litre) of CaCOX3 (molar mass 100), assuming all CaX2+ is converted to oxalate. Give the answer to the nearest integer.
Numerical answer type, answer in ppm, tolerance 1.
Answer: 310 ppm
mmol MnOX4X− = 12.4×0.0100=0.124; mmol oxalate = 0.124×2.5=0.310 = mmol CaX2+ = mmol CaCOX3 equivalent. Mass = 0.310×100=31.0 mg in 0.100 L, so hardness = 310 mg/L.