Use Fe = 56, S = 32, O = 16. A 2.5 g sample containing FeSO4 and inert matter was dissolved in dilute H2SO4 and required 40 mL of 0.05 M KMnO4. The percentage of FeSO4 in the sample is:

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Use Fe = 56, S = 32, O = 16. A $2.5 g$ sample containing $FeSO X_{4}$ and inert matter was dissolved in dilute $H X_{2} SO X_{4}$ and required $40 mL$ of $0.05 M$ $KMnO X_{4}$ . The percentage of $FeSO X_{4}$ in the sample is:

KMnO X_{4}

40 \times 0.05 = 2

mmol;

Fe X^{2 +}

= 2 \times 5 = 10

mmol

= 10 \times 1 0^{- 3} \times 152 = 1.52 g

. Percentage

= 1.52/2.5 \times 100 = 60.8%