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Critical constants and liquefaction
JEE Advanced level
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Difficulty 3 of 3
rg208
For a van der Waals gas, the ratio
T
c
P
c
V
c
in terms of
R
is
A
8
3
R
B
3
8
R
C
R
D
8
27
R
Answer: A
P
c
V
c
=
27
b
2
a
×
3
b
=
9
b
a
and
R
T
c
=
27
b
8
a
. Dividing,
R
T
c
P
c
V
c
=
8
a
/27
b
a
/9
b
=
8
3
, so
T
c
P
c
V
c
=
8
3
R
.
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