At 300 K and 200 atm a gas has Z = 1.125. Assuming the high-pressure form Z = 1 + (Pb)/(RT) and R = 0.0821 L atm K^-1 mol^-1, the value of b in mL mol^-1 (one decimal) is

JEE Main levelNumerical answerDifficulty 2 of 3rg127

At $300 K$ and $200 atm$ a gas has $Z = 1.125$ . Assuming the high-pressure form $Z = 1 + \frac{P b}{RT}$ and $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , the value of $b$ in $mL mo l^{- 1}$ (one decimal) is

Numerical answer type, answer in mL/mol, tolerance 0.2.

b = \frac{( Z - 1 ) RT}{P} = \frac{0.125 \times 24.63}{200} = \frac{3.0788}{200} = 0.01539 L mo l^{- 1} = 15.39 mL mo l^{- 1}

, i.e.

15.4 mL mo l^{- 1}