The critical temperature of oxygen is $154 K$ . Assuming van der Waals behaviour, its Boyle temperature in K (nearest integer) is

Numerical answer type, answer in K, tolerance 1.

Answer: 520 K

T_{c} = 8 a /27 R b

and

T_{B} = a / R b

, so

T_{B} = \frac{27}{8} T_{c} = \frac{27 \times 154}{8} = 519.75 K

, i.e.

520 K

. The experimental Boyle temperature of oxygen (

405 K

) is lower because real gases are not exactly van der Waals.