The Boyle temperature of a gas is $433 K$ and $b = 0.0391 L mo l^{- 1}$ . Using $T_{B} = a / R b$ and $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , the constant $a$ in $L^{2} atm mo l^{- 2}$ (two decimals) is

Numerical answer type, answer in L^2 atm/mol^2, tolerance 0.02.

Answer: 1.39 L^2 atm/mol^2

a = R b T_{B} = 0.0821 \times 0.0391 \times 433 = 1.3900

, i.e.

1.39 L^{2} atm mo l^{- 2}

. These are the constants of nitrogen.