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For a van der Waals gas the Boyle temperature $T_{B}$ and the inversion temperature $T_{i}$ are related as

A $T_{i} = T_{B}$
B $T_{i} = 2 T_{B}$
C $T_{i} = T_{B} /2$
D $T_{i} = 4 T_{B}$

Answer: B

For a van der Waals gas

T_{B} = a / R b

and

T_{i} = 2 a / R b

. Hence

T_{i} = 2 T_{B}

. Below

T_{i}

a gas cools on Joule-Thomson expansion.

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