MolSynapsequestion bank

MolSynapse / Question bank / Real Gases / Boyle temperature and inversion temperature

JEE Main levelOne or more correct optionsDifficulty 2 of 3rg028

The Boyle temperature of a van der Waals gas is $412 K$ . Which of the following are correct for this gas?

AIts inversion temperature is $824 K$
BIts critical temperature is about $122 K$
CAt $500 K$ it cools on Joule-Thomson expansion
DAt $300 K$ its compressibility factor is greater than 1 at low pressure

Answer: A, B, C

T_{i} = 2 T_{B} = 824 K

(A true).

T_{c} = 8 T_{B} /27 = 8 \times 412/27 = 122.1 K

(B true).

500 K

is below

T_{i}

, so the gas cools on throttling (C true).

300 K

is below

T_{B}

, so attraction dominates and

Z

is less than 1 at low pressure (D false).

Practice Real Gases More on Boyle temperature and inversion temperature

Previous questionNext question

More questions on Boyle temperature and inversion temperature