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JEE Advanced levelSingle correct optionDifficulty 3 of 3pl232

A short fragment of a copolymer chain (three repeat units, end groups shown) is drawn. It is a synthetic rubber made by free radical copolymerisation, the diene being added 1,4. Which pair of monomers, shown as two molecules among the structures, gives it?

  1. AStructure A
  2. BStructure B
  3. CStructure C
  4. DStructure D

Answer: D

A phenyl group on one carbon of the backbone indicates styrene, and the repeat units containing -CH2-CH=CH-CH2- come from buta-1,3-diene added 1,4, so the copolymer is Buna-S (SBR). Isoprene would leave a methyl branch on each C=C, alpha-methylstyrene would give a quaternary carbon, and chloroprene would give a Cl on the double bond.
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