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JEE Advanced levelSingle correct optionDifficulty 3 of 3pt185

The sum of the oxidation numbers of oxygen in $OF X_{2}$ , $H X_{2} O X_{2}$ , $KO X_{2}$ and $Na X_{2} O$ (one oxygen atom considered in each) is

A $- 1.5$
B $- 2.5$
C $- 0.5$
D $- 3.5$

Answer: A

Oxygen is

+ 2

in

OF X_{2}

because F is more electronegative,

- 1

in the peroxide

H X_{2} O X_{2}

,

- 1/2

in the superoxide

KO X_{2}

and

- 2

in the oxide

Na X_{2} O

. The sum is

2 - 1 - 0.5 - 2 = - 1.5

.

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