JEE Main levelSingle correct optionDifficulty 2 of 3ph178
Given E∘ (V): FX2/FX−=2.87, ClX2/ClX−=1.36, BrX2/BrX−=1.09, IX2/IX−=0.54. Which reaction is spontaneous under standard conditions?
ABrX2+2ClX−2BrX−+ClX2
BClX2+2IX−2ClX−+IX2
CIX2+2BrX−2IX−+BrX2
DIX2+2ClX−2IX−+ClX2
Answer: B
A reaction is spontaneous when Ecell∘=Ecathode∘−Eanode∘>0. For ClX2 oxidising IX− it is 1.36−0.54=+0.82V. The other three give −0.27, −0.55 and −0.82V, so they are non-spontaneous.