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JEE Main levelSingle correct optionDifficulty 2 of 3ph136

The shape, hybridisation of Xe and oxidation state of Xe in the perxenate ion $XeO X_{6} X^{4 -}$ are respectively

Aoctahedral, $s p^{3} d^{2}$ , +8
Boctahedral, $s p^{3} d^{2}$ , +6
Ctetrahedral, $s p^{3}$ , +8
Dpentagonal bipyramidal, $s p^{3} d^{3}$ , +8

Answer: A

Oxidation state:

x + 6 (- 2) = - 4

, so

x = + 8

. Xe has six O neighbours and no lone pair, so six electron pairs give

s p^{3} d^{2}

and an octahedral ion.

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