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JEE Main levelSingle correct optionDifficulty 2 of 3ph134

The structure of $XeO X_{2} F X_{2}$ and the number of lone pairs on Xe are respectively

Asee-saw, 1
Btetrahedral, 0
CT-shaped, 2
Dsquare planar, 2

Answer: A

Xe forms four sigma bonds (2 Xe-O, 2 Xe-F) and keeps one lone pair, so 5 electron pairs (

s p^{3} d

). The lone pair is equatorial, giving a see-saw shape.

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