In which of the following does Xe carry no lone pair?

A $XeO X_{3}$
B $XeO X_{4}$
C $XeOF X_{4}$
D $XeF X_{4}$

Answer: B

XeO4 has four sigma bonds and Xe uses all eight valence electrons in bonding, so there is no lone pair and the shape is tetrahedral. XeO3 and XeOF4 each have one lone pair; XeF4 has two.

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