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JEE Advanced levelSingle correct optionDifficulty 3 of 3ph045

Fluorine reacts with cold dilute (2 per cent) aqueous $NaOH$ . Which oxygen-containing product forms, and what is the oxidation state of oxygen in it?

A $OF X_{2}$ , $+ 2$
B $OF X_{2}$ , $- 2$
C $O X_{2}$ , $0$
D $NaOF$ , $+ 1$

Answer: A

The reaction is

2 F X_{2} + 2 NaOH 2 NaF + OF X_{2} + H X_{2} O

. Fluorine is more electronegative than oxygen, so in

OF X_{2}

each F is -1 and oxygen is +2, not -2.

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